Find the mean absolute deviation for the numbers 30, 45, 52, 48, 100, 45, 42, 45.

Given numbers
30, 4s, 52, 48, 100, 45, 47,45
Step 1: find "mean"
= (30 + 45 + 52 + 48 + 100 + 45 + 42 + 45) / 8
= 50.875
Step 2: Find absolute value of each result,Here result is difference between eachvelue in the date and mean.
(30 - 50.875) = 20.875
(45 - 50.875) = 5.875
(52 - 50.875) = 1.125
(48 - 50.875) = 2.875
(100 - 50.875) = 49.125
(45 - 50.875) = 5.875
(42 - 50.875) = 8.875
(45 - 50.875) = 5.875
Step 3: Find the average of step 2 result's
(20.875 + 5.875 + 1.125 + 2.875 + 49.125 + 5.875 + 8.875 + 5.875) / 8
= 12.5625
The mean absolute deviation is 12. 5625

To find the mean absolute deviation, you have to take several steps. The mean absolute deviation is the average distance away from the mean value of a dataset of each datapoint.
First, you need to find the mean of the data by summing them all and dividing by the count: (30 + 45 + 52 + 48 + 100 + 45 + 42 + 45)/8 = 50.875
Then, subtract each number from the mean and take the absolute value of each result:
abs(30 - 50.875) = 20.875
abs(45 - 50.875) = 5.875
abs(52 - 50.875) = 1.125
abs(48 - 50.875) = 2.875
abs(100 - 50.875) = 49.125
abs(45 - 50.875) = 5.875
abs(42 - 50.875) = 8.875
abs(45 - 50.875) = 5.875
Finally, take the mean of all these values in the same way as before.
(20.875 + 5.875 + 1.125 + 2.875 + 49.125 + 5.875 + 8.875 + 5.875)/8 = 12.5625